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16.在光滑的水平面上.用一根輕繩系著一個(gè)質(zhì)量為3kg的小球以10m/s的速度繞O點(diǎn)做勻速圓周運(yùn)動(dòng).半徑為4m,若運(yùn)動(dòng)到A點(diǎn).突然將繩再放長(zhǎng)4m, 繩繃緊后小球轉(zhuǎn)入到另一軌道上做勻速圓周運(yùn)動(dòng).求:⑴小球從放繩開始到運(yùn)動(dòng)到O點(diǎn)另一側(cè)與AO兩點(diǎn)共線的B點(diǎn)所用的時(shí)間? 查看更多

 

題目列表(包括答案和解析)

精英家教網(wǎng)在光滑的水平面上,用一根輕繩系著一個(gè)質(zhì)量為3kg的小球以10m/s的速度繞O點(diǎn)做勻速圓周運(yùn)動(dòng),半徑為4m,若運(yùn)動(dòng)到A點(diǎn),突然將繩再放長(zhǎng)4m,繩繃緊后小球轉(zhuǎn)入到另一軌道上做勻速圓周運(yùn)動(dòng).求:
(1)小球從放繩開始到運(yùn)動(dòng)到O點(diǎn)另一側(cè)與AO兩點(diǎn)共線的B點(diǎn)所用的時(shí)間?
(2)在B點(diǎn)繩子所受到的拉力.

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(10分)在光滑的水平面上,用一根輕繩系一個(gè)質(zhì)量為3千克小球,以10m/s速度做勻速圓周運(yùn)動(dòng),半徑為4m,若運(yùn)動(dòng)到A點(diǎn),突然把繩再放長(zhǎng)4米,繩繃緊后小球轉(zhuǎn)入另一軌道上做勻速圓周運(yùn)動(dòng),求:

(1)小球從放繩開始到運(yùn)動(dòng)到O點(diǎn)的另一側(cè)與AO共線的B點(diǎn)所需的時(shí)間。

(2)在B點(diǎn)繩子所受的拉力。

 

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(10分)在光滑的水平面上,用一根輕繩系一個(gè)質(zhì)量為3千克小球,以10m/s速度做勻速圓周運(yùn)動(dòng),半徑為4m,若運(yùn)動(dòng)到A點(diǎn),突然把繩再放長(zhǎng)4米,繩繃緊后小球轉(zhuǎn)入另一軌道上做勻速圓周運(yùn)動(dòng),求:

(1)小球從放繩開始到運(yùn)動(dòng)到O點(diǎn)的另一側(cè)與AO共線的B點(diǎn)所需的時(shí)間。
(2)在B點(diǎn)繩子所受的拉力。

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(10分)在光滑的水平面上,用一根輕繩系一個(gè)質(zhì)量為3千克小球,以10m/s速度做勻速圓周運(yùn)動(dòng),半徑為4m,若運(yùn)動(dòng)到A點(diǎn),突然把繩再放長(zhǎng)4米,繩繃緊后小球轉(zhuǎn)入另一軌道上做勻速圓周運(yùn)動(dòng),求:

(1)小球從放繩開始到運(yùn)動(dòng)到O點(diǎn)的另一側(cè)與AO共線的B點(diǎn)所需的時(shí)間。
(2)在B點(diǎn)繩子所受的拉力。

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在光滑的水平面上,用一根輕繩系著一個(gè)質(zhì)量為3 kg的小球以10 m/s的速度繞O點(diǎn)做勻速圓周運(yùn)動(dòng),半徑為4 m,若運(yùn)動(dòng)到A點(diǎn),突然將繩再放長(zhǎng)4 m,繩繃緊后小球轉(zhuǎn)入到另一軌道上做勻速圓周運(yùn)動(dòng).求:

(1)小球從放繩開始到運(yùn)動(dòng)到O點(diǎn)另一側(cè)與AO兩點(diǎn)共線的B點(diǎn)所用的時(shí)間?

(2)在B點(diǎn)繩子所受到的拉力.

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一、本題共10小題,每小題5分.每小題給出的四個(gè)選項(xiàng)中,有的小題只有一個(gè)選項(xiàng)正確,有的小題有多個(gè)選項(xiàng)正確,全部選對(duì)得5分,選不全得3分,有選錯(cuò)或不答得0分.

題號(hào)

1

2

3

4

5

6

7

8

9

10

答案

AB

D

B

D

AC

C

A

D

B

BCD

學(xué)科網(wǎng)(Zxxk.Com)二、本題共2小題,共18分

  11(4分)偏小

12.(8分)(1)電路圖(4分)

 

 

(2)9.0,10.0 (每空2分)

 

13.(4分)右  (2分)          t=  (2分)

14、(13分)解:(1)飛船在運(yùn)行過(guò)程中萬(wàn)有引力提供向心力

 

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2分)

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

由(2) (3)得:飛船運(yùn)行周期:

2分)

 

 

 

 

 

 

 

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15.(13分)解(1)如圖所示,帶電質(zhì)點(diǎn)在重力mg(大小及方向均已知)、洛倫茲力qv0B(方向已知)、電場(chǎng)力qE(大小及方向均未知)的作用做勻速直線運(yùn)動(dòng)。根據(jù)力三角形知識(shí)分析可知:當(dāng)電場(chǎng)力方向與磁場(chǎng)方向相同時(shí),場(chǎng)強(qiáng)有最小值。

學(xué)科網(wǎng)(Zxxk.Com)根據(jù)物體的平衡規(guī)律有

                     (1分)

                     (1分)

解得                     (2分)

                          (2分)

(2)當(dāng)電場(chǎng)力和重力平衡時(shí),帶點(diǎn)質(zhì)點(diǎn)才能只受洛倫茲力作用做勻速圓周運(yùn)動(dòng)

則有:                 (1分)

得:                   (1分)

要使帶電質(zhì)點(diǎn)經(jīng)過(guò)x軸,圓周的直徑為   (2分)

根據(jù)(1分)

                           (2分)

16.(12分)解:⑴小球做勻速圓周運(yùn)動(dòng),突然放繩則小球以原有的速度做勻速直線運(yùn)動(dòng)到C,在C點(diǎn)處一瞬間8m繩突然拉直,沿繩方向的速度vyP突變?yōu)?,而小球?qū)⒁詖x做勻速圓周運(yùn)動(dòng),到達(dá)B點(diǎn),

學(xué)科網(wǎng)(Zxxk.Com)由幾何關(guān)系可知:S1=AC=   (1分)

∠AOC=60°=π/3

     (2分)                      

∠BOC=120°=2π/3     (1分)

在C點(diǎn),由矢量三角形可知:vx=vcos60°=v/2    (1分)

    (2分)

 (2分)

學(xué)科網(wǎng)(Zxxk.Com)(2)在B點(diǎn),則有:    (3分)

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      1. 解:(1)小物塊沿斜面下滑的過(guò)程中受力情況如圖所示

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