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(1)求數(shù)列; 查看更多

 

題目列表(包括答案和解析)

求數(shù)列
1
1+
2
,
1
2
+
3
,…,
1
n
+
n+1
,…
的前n項和
 

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14、求數(shù)列{(-1)n•n}的前2010項的和S2010

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求數(shù)列2,4,8,16,…前十項的和.

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求數(shù)列1
1
2
,2
1
4
,3
1
8
,4
1
16
,…
前n項的和.

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求數(shù)列的前n項和:1+1,
1
a
+4,
1
a2
+7,…,
1
an-1
+3n-2,…

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一.選擇題

1―5  CBABA   6―10  CADDA

二.填空題

11.       12.()       13.2          14.         15.

16.(1,4)

三.解答題

數(shù)學(xué)理數(shù)學(xué)理17,解:①         =2(1,0)                      (2分)             

        ?,                                        (4分)

      • <legend id="m8vdo"><track id="m8vdo"></track></legend>

        ?

                cos              =

         

                由,  ,    即B=              (6分)

                                                       (7分)

                                                                (9分)

        ,                                                         (11分)

        的取值范圍是(,1                                                      (13分)

        18.解:①設(shè)雙曲線方程為:  ()                                 (1分)

        由橢圓,求得兩焦點,                                           (3分)

        ,又為一條漸近線

        , 解得:                                                     (5分)

                                                            (6分)

        ②設(shè),則                                                      (7分)

              

        ?                             (9分)

        ,  ?              (10分)

                                                        (11分)

          ?

        ?                                        (13分)

            1.   單減區(qū)間為[]        (6分)

               

              ②(i)當(dāng)                                                      (8分)

              (ii)當(dāng)

              ,  (),,

              則有                                                                     (10分)

              ,

                                                             (11分)

                在(0,1]上單調(diào)遞減                     (12分)

                                                               (13分)

              20.解:①       

                                                                      (2分)

              從而數(shù)列{}是首項為1,公差為C的等差數(shù)列

                即                                (4分)

               

                 即………………※              (6分)

              當(dāng)n=1時,由※得:c<0                                                    (7分)

              當(dāng)n=2時,由※得:                                                 (8分)

              當(dāng)n=3時,由※得:                                                 (9分)

              當(dāng)

                  (

                                                        (11分)

                                       (12分)

              綜上分析可知,滿足條件的實數(shù)c不存在.                                    (13分)

              21.解:①設(shè)過A作拋物線的切線斜率為K,則切線方程:

                                                                              (2分)

                  即

                                                                                                                 (3分)

              ②設(shè)   又

                   

                                                                       (4分)

              同理可得 

                                                              (5分)

              又兩切點交于  ,

                                             (6分)

              ③由  可得:

               

                                                              (8分)

                                (9分)

               

              當(dāng) 

              當(dāng) 

                                                                   (11分)

              當(dāng)且僅當(dāng),取 “=”,此時

                                                     (12分)

              22.①證明:由,    

                即證

                ()                                    (1分)

              當(dāng)  

                    即:                          (3分)

                ()    

              當(dāng)   

                 

                                                                       (6分)

              ②由      

              數(shù)列

                                                            (8分)

              由①可知, 

                                  (10分)

              由錯位相減法得:                                       (11分)

                                                  (12分)